What anger consumes Mother Earth?

 

These days:

What anger consumes Mother Earth?

Sometimes she shivers in Richter Scale,

Sometimes she spews unholy ash,

Sometimes she calls

The big birds to crash.

Sometimes she makes

The Titanics to dash.

What anger consumes Mother Earth?

Answer to Walking Track Quiz

 

Answer to Walking Track Quiz: https://hunterfiftyfour.blogspot.com/2025/11/walking-track-quiz.html

I measure my own lap time T_lap — the time I take to go once around the 1 km track.

I keep a record of the time t between two consecutive meetings with the other walker

The rule:

If t<1/2  T_lap ​ → I am slower

If t>1/2 T_lap →  I am faster.

If t=1/2  T_lap ​ → same speed.

Intuitively:

Between two successive meetings I always walk the same distance along the track. Call that distance ‘d’.

Now, this ‘d’ distance has contribution in terms of metres covered both by me and the other walker. If my contribution to ‘d’ is less than half the total loop – in this case 0.5 km – I am going slower. If mine and the other walker have equal contribution, we are going at same speed. If my contribution to ‘d’ is more, then I’m faster.

Translate this to time:

If ‘t’, the time between two consecutive meetings, is greater than half my lap time, then I’m slower than the other walker. If half my lap time is equal to ‘t’, then our speeds are equal. Else, my speed is more than the other walker’s speed.

Walking Track Quiz

 

We have a closed loop walking track of 1 km in our neighbourhood. Some walkers go clockwise, some anticlockwise. If I'm one of the walkers who is going clockwise, and I keep meeting another walker who is walking anticlockwise at different spots in the closed loop track, as I and the other walker circle the track, how do I know which walker is going fast/slow? Of course, if both of us meet at the same spot, I know that both of us are doing the same speed.

Assumptions: 1. Both walkers maintain constant speed.  2. I have a phone that can give me my lap time. I can  also find the time between successive meetings on the track with the help of the same phone. (Hint?) No other aid is available.

No formal proof is required. Only intuitive answer with justification will do.

Post Script: All of the above is actual. Not a hypothetical question. We need to remember that both walkers may not begin at the same time from the starting point. Indeed that would be the norm, rather than the exception. For example, I may meet the other walker just after I start my clockwise traverse.

Better than Artificial Intelligence

 

The days of रुकावट के लिए खेद है,

The days of black and white,

The days when Left was left,

The days when Right was right.

The days of Chitrahaar,

The days of power cut बारम बार,

Those days of natural stupidity,

 Indeed, much better by far.

How far is heaven?

 

Did you know that The Puppeteer that is holding the end of the string that holds the world is at a point that is 4.6 × 10²⁷ metres (or, 490 billion light years) away?

Now, this is 10.5 times the radius of the observable universe (that is. far larger than the universe we can see). That’s how far heaven is located. Perhaps, that is the reason we never see the Puppeteer(being outside the observable universe).

How did I arrive at this figure?

I asked OpenAI this: The yugs are more like a pendulum than a circle, right? If we add all the yugs' days and make a pendulum (with the bob as the earth) with 'g' at 9.81m/sec², what would be the length of the string from where the bob is hanging? Which yuga / which year would be at the bottom most in the pendulum swing?

OpenAI calculated thus:

Nice idea — fun to make myth + mechanics meet. I’ll make one clear assumption (and then do the arithmetic):

Assumption I use: the “total of all the yugs” = one Mahayuga = Satya (Kṛta) + Tretā + Dvāpara + Kali = 4,320,000 years (traditional Hindu scheme: 1,728,000 + 1,296,000 + 864,000 + 432,000).
I map the entire Mahayuga to one full period T of a simple pendulum with acceleration g = 9.81 m/sec².

A simple pendulum period:

T = 2π(√L/g)

L =  g(T/2π)²

Convert the Mahayuga to seconds: T=4,320,000 yr×(days/yr)×24×3600

Result:

Using 365 days / year

T ≈ 1.36236×10¹⁴ seconds

L ≈ 4.61×10²⁷ metres

To make those numbers easier to picture:

• L≈4.6×10²⁷metres  ≈ 4.9×10¹¹ light-years (≈ 490 billion light-years).
• That is ≈ 10.5 times the radius of the observable universe (i.e. far larger than the universe we can see).

That is how far heaven is located.

Which yuga / which year is the bottom-most point of the swing?

If you start the pendulum at one extreme at t=0 (start of the Mahayuga) then the pendulum is vertical (bottom-most) after T/4.
T/4 corresponds to one quarter of the Mahayuga in time:

4,320,000/4=1,080,000 years

So the bottom-most point occurs 1,080,000 years into the Mahayuga. Since Satya/Kṛta lasts 1,728,000 years, that 1,080,000-th year falls inside Satya/Kṛta — roughly a bit past the middle of Satya, well before Treta begins.

Just think about it, friends: Kaliyug will go in a jiffy…whoosh! But beware! We have to traverse it twice before we go into Dwapar yug: one on the upswing, one on the downswing.

 

 

 

Bend the reality again, and again

 

Dance, and it will rain,

Sing, and the stone will melt,

Call, and she'll return,

Bend the reality again,

And again.

आज हमारा नाइन इलेवन दिवस है

 

आज हमारा नाइन इलेवन दिवस है। आज के दिन, एक सौ पचास साल पहले, बंकिमजी ने अंग्रेज़ों को भारत से नौ दो ग्यारह  (9/11)होने का आह्वान किया था!

वन्दे मातरम्!